(x+2)(12x^3-3x^2+x+1)=0

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Solution for (x+2)(12x^3-3x^2+x+1)=0 equation:


Simplifying
(x + 2)(12x3 + -3x2 + x + 1) = 0

Reorder the terms:
(2 + x)(12x3 + -3x2 + x + 1) = 0

Reorder the terms:
(2 + x)(1 + x + -3x2 + 12x3) = 0

Multiply (2 + x) * (1 + x + -3x2 + 12x3)
(2(1 + x + -3x2 + 12x3) + x(1 + x + -3x2 + 12x3)) = 0
((1 * 2 + x * 2 + -3x2 * 2 + 12x3 * 2) + x(1 + x + -3x2 + 12x3)) = 0
((2 + 2x + -6x2 + 24x3) + x(1 + x + -3x2 + 12x3)) = 0
(2 + 2x + -6x2 + 24x3 + (1 * x + x * x + -3x2 * x + 12x3 * x)) = 0
(2 + 2x + -6x2 + 24x3 + (1x + x2 + -3x3 + 12x4)) = 0

Reorder the terms:
(2 + 2x + 1x + -6x2 + x2 + 24x3 + -3x3 + 12x4) = 0

Combine like terms: 2x + 1x = 3x
(2 + 3x + -6x2 + x2 + 24x3 + -3x3 + 12x4) = 0

Combine like terms: -6x2 + x2 = -5x2
(2 + 3x + -5x2 + 24x3 + -3x3 + 12x4) = 0

Combine like terms: 24x3 + -3x3 = 21x3
(2 + 3x + -5x2 + 21x3 + 12x4) = 0

Solving
2 + 3x + -5x2 + 21x3 + 12x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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